lawlberg
Booth Babe
Sorry in advance, these questions come up all the time. I think my question is slightly different just because I'm being stubborn and am going to try the resistor approach first, then when it doesn't work I'll track down an electronic flasher.
My question:
Since I am going to attach aftermarket LED signals in addition to the integrated signal, my plan was to tap into the resistor bundle that came with the Motodynamic taillight, here:
My understanding of LEDs is that they draw such a little amount of current, one resistor should be enough for both LED signals per side (integrated and the ones that stick out), whereas if I use a resistor for the integrated and the sticking out ones it would slow down the flash too much, since the bike was designed for 4, not 6 turns signals.
Anyway, I'll most likely do this and prove my theory wrong when the signals show up (2wheels) from China, unless someone here tells me that my understanding is fundamentally flawed.
Side note:
Assuming there are two wires per signal, I'll ground the second (hopefully black wire) to the subframe, instead of tapping into the wire before the resistor, right?
My question:
Since I am going to attach aftermarket LED signals in addition to the integrated signal, my plan was to tap into the resistor bundle that came with the Motodynamic taillight, here:
My understanding of LEDs is that they draw such a little amount of current, one resistor should be enough for both LED signals per side (integrated and the ones that stick out), whereas if I use a resistor for the integrated and the sticking out ones it would slow down the flash too much, since the bike was designed for 4, not 6 turns signals.
Anyway, I'll most likely do this and prove my theory wrong when the signals show up (2wheels) from China, unless someone here tells me that my understanding is fundamentally flawed.
Side note:
Assuming there are two wires per signal, I'll ground the second (hopefully black wire) to the subframe, instead of tapping into the wire before the resistor, right?