Question of the Day #359 (13/10/10)

[Kazza]

My tap is leaking! It is dripping 3 drops per second and each drop is 1 1/3ml.

If I had to wait a whole year for the plumber, how much water would be wasted?


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[Popeye70]

PM sent. :rockon:

 

[Dan]

PM is on its way

 

[chaskell27]

pm has been sent

 

[ELIZABETH]

filling up the swimming pool??
PM sent

 

[sxty8goats]

this question hurts my engineering head.

A drop can vary in size from 50ul to 90ul (.05ml to .09ml)

A year also has multiple definitions.

uGg.

PM Sent (soon) answering within the paramiters of the question...

 

[viviifz6]

PM has been Sent!
Aaron

 

[sxty8goats]

Saw this and thought Kaza might get a kick out of it:

 

[rsw81]

Oh, another mathy! That means I stand an actual chance at getting it right! PM Sent.:thumbup:

 

[Kazza]

Saw this and thought Kaza might get a kick out of it:

:cheer: :cheer:

 

[MHS]

PM S e n t !

 

[Kazza]

My tap is leaking! It is dripping 3 drops per second and each drop is 1 1/3ml.

If I had to wait a whole year for the plumber, how much water would be wasted?

Water lost per second: 3 * (1 1/3 mL) = 4mL
Number of seconds in one year:
60s/min x 60 min/hr x 24hr/day x 365d/y = 31 536 000 s
Water lost in one year = 4mL/s * 31 536 000 s
= 126 144 000 mL
Convert to Litres:
126 144 000mL * 1L/1000 mL = 126 144 litres


REP & CASINO CASH WINNERS:

Popeye70
Dan
Viviifz6


REP WINNERS:

Sxty8goats
Rsw81


And Sxty8goats, thanks for so many answers - Astronomical year, Standard Calendar year and Leap year