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Oz's Question of the day #219 (19/2/10) Maths !

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OZXJR

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My wife and I have have two children.
The probability that the first child is a boy, is 50%.
The probability that the second child is a boy, is also 50%.
I will tell you that one child is a boy.

What is the probability that our other child is also a boy ?.

PM answers please.
 
Last edited:
PM'd my correct (fingers crossed) answer with an explanation . . .

bit late in the day as I've not been at work and this is my first time at a PC today

(better be right after blowing my trumpet) :eek:
 
Answer:33%

Rep and casino cash winners:Fz6sa and Coopdman

Nicely worked out guys.

Here is Coops answer .

First Child______Second Child
Boy_______________Boy
Boy_______________Girl
Girl_______________Boy
Girl_______________Girl <-- not possible

So we have a total of 3 possibilities. Taking the known boy out of the equation we see the options become, (Boy, Girl, Girl).

So the probability that you have a second boy is 1 in 3, or 33.333333333%
 
I'm going to have to disagree. By using Coop's exact logic, order of children is irrelevant (i.e. boy-girl is the same as girl-boy). That reduces it to only two choices which is boy-boy or the combination of boy-girl/girl-boy. This is not a permutation. Had the problem stated that the first child was a boy, then Coop's logic would hold true. All it says is one child is a boy.
 
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