Oz's Question of the day #56(29/7/09)

[OZXJR]

Nine billiard-balls are lying in front of you. Except for one they all have the same weight.
The exception is a little bit heavier than the others.
What is the minimum number of times you have to use a scale in order to find the heavier billiard ball?


PM answers please.

 

[4fun]

PM sent

 

[99vengeur]

Pm'ed my guess.

 

[SirIsaac]

Nine billiard-balls are lying in front of you. Except for one they all have the same weight.....

Answer PMed.

 

[GastonJ]

Answer PM'd. I didn't include the working of it though, hope you won't hold that against me

 

[fireman]

PM'd my answer

 

[trick6]

PMed my guess

 

[OZXJR]

Answer:2
If your lucky and the heavy one is in the first two,the worst you can do is eight.
I never said that one was the cue ball either ,lol

Rep and casino cash winners:Clockworkjon,TravisJ37 and Shuckle.

Rep winners:Goker,Westgoingzax,GastonJ and Fireman

congrats guys and thanks for playing.

 

[westgoingzax]

I'm one of the rep winners. Thanks for the questions Oz!